The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, (dQ/dt) through the rod in a steady state is given by:
A
dQ/dt = (k(T₁ - T₂))/LA
B
dQ/dt = kLA(T₁ - T₂)
C
dQ/dt = (kA(T₁ - T₂))/L
D
dQ/dt = (k(L(T₁ - T₂)))/A

Question

The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, (dQ/dt) through the rod in a steady state is given by:

A

dQ/dt = (k(T₁ - T₂))/LA

B

dQ/dt = kLA(T₁ - T₂)

C

dQ/dt = (kA(T₁ - T₂))/L

D

dQ/dt = (k(L(T₁ - T₂)))/A

Accepted Answer

dQ/dt = (kA(T₁ - T₂))/L

Answer

dQ/dt = (k(T₁ - T₂))/LA

Answer

dQ/dt = kLA(T₁ - T₂)

Answer

dQ/dt = (k(L(T₁ - T₂)))/A

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