AIPMT MAINS 2008 Physics Projectile Motion MCQ Question
A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be
zero
2 mv
mv√2
mv√2
Correct Answer
Detailed Explanation
The change in momentum is calculated using the formula 2mv sinθ. At 45°, sinθ = √2/2, leading to a change in momentum of mv√2.
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