AIPMT MAINS 2009 Physics Kepler's Laws MCQ Question
The Figure shows elliptical orbit of a planet m about the sum S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet of move from C to D and t2 is the time to move from A to B then:
t1 = 4t2
t1 = 2t2
t1 = t2
t1 > t2
Correct Answer
Detailed Explanation
The time taken is proportional to the area swept, so if area SCD is twice SAB, then t1 = 2t2.
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