AIPMT MAINS 2011 Chemistry Colligative Properties MCQ Question
200 mL of an aqueous solution of a protein contains its 1.26 g. The Osmotic pressure of this solution at 300 K is found to be 2.57 × 10⁻³ bar. The molar mass of protein will be (R = 0.083 L bar mol⁻¹ K⁻¹)
31011 g mol⁻¹
61038 g mol⁻¹
51022 g mol⁻¹
122044 g mol⁻¹
Correct Answer
Detailed Explanation
Using the formula for osmotic pressure π = (w × R × T) / (M × V), the molar mass M is calculated to be 61038 g mol⁻¹.
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