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AIPMT MAINS2009Chemistry-Electrochemistry

AIPMT MAINS 2009 Chemistry Electrolysis MCQ Question

Type: MCQ-numerical-Medium-Class 12

Al₂O₃ is reduced by electrolysis at low potentials and high currents. If 4.0 × 10⁴ amperes of current is passed through molten Al₂O₃ for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency. At. mass of Al = 27 g mol⁻¹ )

A

8.1 × 10⁴ g

B

2.4 × 10⁵ g

C

1.3 × 10⁴ g

D

9.0 × 10³ g

Correct Answer

Option A

Detailed Explanation

Using Faraday's laws of electrolysis, the mass of Al produced is calculated as: mass = (current × time × molar mass) / (n × F), where n is the number of electrons and F is Faraday's constant.

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