AIPMT MAINS2012Chemistry-Gaseous State

AIPMT MAINS 2012 Chemistry Graham's Law of Effusion MCQ Question

Type: MCQ-numerical-Medium

A certain gas takes three times as long to effuse out as helium. Its molecular mass will be:

A

27 u

B

36 u

C

64 u

D

9 u

Correct Answer

Option B

Detailed Explanation

Using Graham's law of effusion, r ∝ 1/√M. If the gas takes three times as long, its rate is 1/3 that of helium. Solving 1/9 = 4/M gives M = 36 u.

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