AIPMT MAIN2008Physics-Electromagnetism
AIPMT MAIN 2008 Physics Self-Inductance MCQ Question
Type: MCQ-numerical-Medium-Class 12
A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 × 10⁻³ Wb. The self-inductance of the solenoid is
A
4.0 henry
B
2.5 henry
C
2.0 henry
D
1.0 henry
Correct Answer
Option D
Detailed Explanation
Using the formula NΦ = Li, where N = 500, Φ = 4 × 10⁻³, and i = 2, we find L = 1.0 henry.
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