AIPMT MAIN2008Physics-Electromagnetism

AIPMT MAIN 2008 Physics Self-Inductance MCQ Question

Type: MCQ-numerical-Medium-Class 12

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 × 10⁻³ Wb. The self-inductance of the solenoid is

A

4.0 henry

B

2.5 henry

C

2.0 henry

D

1.0 henry

Correct Answer

Option D

Detailed Explanation

Using the formula NΦ = Li, where N = 500, Φ = 4 × 10⁻³, and i = 2, we find L = 1.0 henry.

Found an issue with this question?