MarksRiser
MarksRiser
AIPMT MAIN2008Physics-Mechanics

AIPMT MAIN 2008 Physics Projectile Motion MCQ Question

Type: MCQ-numerical-Medium-Class 11

A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be

A

zero

B

2 mv

C

mv√2

D

mv√2

Correct Answer

Option D

Detailed Explanation

The change in momentum is calculated using the formula 2mv sinθ. At 45°, sinθ = √2/2, leading to a change in momentum of mv√2.

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