MarksRiser
MarksRiser
AIPMT MAIN2008Physics-Kinematics

AIPMT MAIN 2008 Physics Equations of Motion MCQ Question

Type: MCQ-numerical-Medium-Class 11

The distance travelled by a particle starting from rest and moving with an acceleration 43 ms2\frac{4}{3} \text{ ms}^{-2} in the third second is

A

193 m\frac{19}{3} \text{ m}

B

6 m

C

4 m

D

103 m\frac{10}{3} \text{ m}

Correct Answer

Option D

Detailed Explanation

Using the formula for distance traveled in the nth second, Sn=u+a2(2n1)S_n = u + \frac{a}{2} (2n - 1), with initial velocity u=0u = 0, acceleration a=43 ms2a = \frac{4}{3} \text{ ms}^{-2}, and n=3n = 3, the distance is 103 m\frac{10}{3} \text{ m}.

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