AIPMT MAIN2008Chemistry-Chemical Equilibrium

AIPMT MAIN 2008 Chemistry Dissociation Equilibrium MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The dissociation equilibrium of a gas AB₂ can be represented as, 2AB₂ (g) ⇌ 2AB (g) + B₂ (g). The degree of dissociation is 'x' and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant Kₚ and total pressure P is

A

KpP\frac{K_{p}}{P}

B

2KpP\frac{2K_{p}}{P}

C

(2KpP)1/3\left( \frac{2K_{p}}{P} \right)^{1/3}

D

(2KpP)1/2\left( \frac{2K_{p}}{P} \right)^{1/2}

Correct Answer

Option C

Detailed Explanation

The equilibrium expression for the dissociation is derived from the equilibrium concentrations. The degree of dissociation 'x' is related to the equilibrium constant Kₚ and pressure P by the expression x3=2KpPx^3 = \frac{2K_{p}}{P}, leading to x=(2KpP)1/3x = \left( \frac{2K_{p}}{P} \right)^{1/3}.

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