AIIMS 2014 Zoology Population Genetics MCQ Question
At a particular locus, frequency of ‘A’ allele is 0.6 and that of ‘a’ is 0.4. What would be the frequency of heterozygotes in a randomly mating population of equilibrium?
0.16
0.36
0.48
0.24
Correct Answer
Detailed Explanation
The frequency of heterozygotes in a population at equilibrium can be calculated using the Hardy-Weinberg principle, which states that the frequency of heterozygotes (Aa) is given by 2pq, where p is the frequency of allele A and q is the frequency of allele a. In this case, p = 0.6 and q = 0.4, so 2pq = 2(0.6)(0.4) = 0.48, making the correct answer C.
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