AIIMS2012Physics-Semiconductors
AIIMS 2012 Physics Transistor Circuits MCQ Question
Type: MCQ-numerical-Hard-Class 12
For a common-emitter transistor, input current is 5 μA, β = 100 circuit is operated at load resistance of 10 kΩ, then voltage across collector emitter will be
A
5 V
B
10 V
C
12.5 V
D
7.5 V
Correct Answer
Option A
Detailed Explanation
Here, I_B = 5 μA = 5 × 10^-6 A β = 100 R_L = 10 kΩ = 10 × 10^3 Ω As β = I_C/I_B or I_C = (100)(5 × 10^-6 A) = 5 × 10^-4 A The voltage across collector emitter is V_CE = I_C R_L = (10 × 10^3)(5 × 10^-4 A) = 5 V
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