AIIMS2019Physics-Optics

AIIMS 2019 Physics Telescope Magnification MCQ Question

Type: MCQ-numerical-Easy-Class 12

For a telescope, focal length of objective lens is 15 cm and focal length of eye piece is 10 mm. If tube length is 16 cm, then find the magnification:

A

150

B

15

C

1.5

D

10

Correct Answer

Option B

Detailed Explanation

The expression for magnification mm is given by the formula m=f0fem = \frac{f₀}{fₑ}, where f0f₀ is the object distance and fefₑ is the image distance. In this case, substituting f0=15f₀ = 15 and fe=1fₑ = 1 yields m=151=15m = \frac{15}{1} = 15, indicating that the image is magnified 15 times. However, if the question implies that the actual magnification observed is 10, it suggests a misunderstanding in the values provided or the context of the question. Options (2) 10, (3) 5, and (4) 20 do not align with the calculation based on the given formula, as they do not reflect the correct ratio derived from the stated distances.

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