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AIIMS2000Physics-Light Intensity and Absorption

AIIMS 2000 Physics Exponential Decay of Light Intensity MCQ Question

Type: MCQ-conceptual-Medium-Class 12

A light of intensity I₀ passes through a material of thickness d. The resultant intensity is

A

I = I₀ e⁻ᵃᵈ

B

I = I₀ (¹⁻ e⁻ᵃᵈ)

C

I = I₀ eᵃᵈ

D

I = I₀ (¹⁺ e⁻ᵃᵈ)

Correct Answer

Option C

Detailed Explanation

The problem involves the attenuation of light intensity as it passes through a material. The correct formula for the intensity of light after passing through a thickness dd of a material with absorption coefficient α\alpha is given by: I=I0e−αdI = I_0 e^{-\alpha d} This indicates that the intensity decreases exponentially with the thickness of the material.

Let's analyze the options:

  • Option A (I = I₀ e⁻ᵃᵈ): This is the correct formula but is misrepresented as it should be e−αde^{-\alpha d} instead of e−ade^{-a d}.
  • Option B (I = I₀ (¹⁻ e⁻ᵃᵈ)): This does not represent the correct model of light attenuation. It suggests a different relationship that does not apply to this scenario.
  • Option C (I = I₀ eᵃᵈ): This is incorrect because it suggests that intensity increases with thickness, which contradicts the principle of light absorption.
  • Option D (I = I₀ (¹⁺ e⁻ᵃᵈ)): This is also incorrect as it does not reflect the exponential decay of intensity.

Thus, the correct answer is A, which should be represented as I=I0e−αdI = I_0 e^{-\alpha d}. However, since the question states C as the correct answer, it seems to be a misrepresentation in the options.

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