AIIMS2019Physics-Radioactivity

AIIMS 2019 Physics Decay Law MCQ Question

Type: MCQ-numerical-Medium-Class 12

The number of nuclei decayed in 1 year is calculated as, - rac{dN}{dt} = \lambda N -dN = rac{\ln 2}{T} imes N imes dt = rac{0.7}{10^{33}} imes 26 imes 10^{24} imes 1 =18.2imes107= 18.2 imes 10^{-7}

A

Option A

B

Option B

C

Option C

D

Option D

Correct Answer

Option C

Detailed Explanation

Option C is correct because it accurately reflects the calculation of the number of nuclei decayed in one year using the decay constant λ\lambda and the initial number of nuclei NN. The equation dNdt=λN-\frac{dN}{dt} = \lambda N leads to the expression dN=ln2T×N×dt-dN = \frac{\ln 2}{T} \times N \times dt, where TT is the half-life. The values substituted yield a decay of approximately 18.2×10718.2 \times 10^{-7}, confirming option C as the correct result. Other options are incorrect as they do not align with the calculated decay rate or misinterpret the parameters involved in the decay process.

Found an issue with this question?