AIIMS2019Physics-Nuclear Physics

AIIMS 2019 Physics Binding Energy MCQ Question

Type: MCQ-numerical-Medium-Class 12

Find BE per nucleon of ⁵⁶Fe where m(⁵⁶Fe) = 55.936 u, mₙ = 1.00727 u, mₚ = 1.007274 u.

A

477.45 MeV

B

8.52 MeV

C

577 MeV

D

10.52 MeV

Correct Answer

Option B

Detailed Explanation

To find the binding energy (BE) per nucleon of 56Fe^{56}\text{Fe}, we first calculate the mass defect using the formula:

Mass defect=Zmp+Nmnm(56Fe)\text{Mass defect} = Z \cdot m_p + N \cdot m_n - m(^{56}\text{Fe})

where Z=26Z = 26 (number of protons) and N=30N = 30 (number of neutrons). Substituting the values, we find the mass defect, convert it to energy using E=Δmc2E = \Delta m \cdot c^2 (with c2c^2 in MeV/u), and then divide by the total number of nucleons (56) to get the BE per nucleon, which results in approximately 8.52 MeV.

Options (A), (C), and (D) are incorrect as they do not reflect the calculated BE per nucleon based on the mass defect and energy conversion, indicating a misunderstanding of the binding energy concept.

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