AIIMS 2018 Physics Magnetic Force MCQ Question

The expression for the force on an electron, given by $F = QVB \sin \theta$, can be derived from the magnetic force acting on a charged particle in a magnetic field. In this case, substituting $Q$ with the charge of the electron $e$ and using the relationship $B = \frac{\mu_0 I}{2\pi d}$ for the magnetic field around a current-carrying wire, we find that $F = \frac{\mu_0 eVI}{2\pi d}$ when $\sin \theta = 1$.

Options B, C, and D introduce incorrect factors in the denominator or numerator, which do not align with the derived expression, thus confirming that option A is the only correct representation of the force on the electron in this context.