AIIMS2019Physics-Magnetism

AIIMS 2019 Physics Magnetic Field and Force MCQ Question

Type: MCQ-numerical-Medium-Class 12

Find force per unit length at P.

Question diagram
A

104 m10^{-4} \text{ m}

B

104 N/m10^{-4} \text{ N/m}

C

3×104 N/m3 \times 10^{-4} \text{ N/m}

D

0.3 N/m0.3 \text{ N/m}

Correct Answer

Option B

Detailed Explanation

The force per unit length F/dlF/dl at point P is calculated using the formula F/dl=iBF/dl = iB, where ii is the current and BB is the magnetic field. Substituting the values, i=5Ai = 5 \, \text{A} and B=2×105TB = 2 \times 10^{-5} \, \text{T}, results in F/dl=5×2×105=104N/mF/dl = 5 \times 2 \times 10^{-5} = 10^{-4} \, \text{N/m}. However, the question states the final answer should be 2×105N/m2 \times 10^{-5} \, \text{N/m} based on the magnetic field calculation, indicating a potential misinterpretation of the values or context. Other options are incorrect as they do not match the calculated force per unit length based on the given parameters.

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