AIIMS 2018 Physics Electric Field and Charge Density MCQ Question

Option A correctly applies the formula $E = \frac{\sigma}{\varepsilon_0 K}$ by substituting the electric field $E = 6 \times 10^5 \, \text{N/C}$, the permittivity of free space $\varepsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2$, and the dielectric constant $K = 6$. This leads to the calculation of charge density $\sigma$ as $\sigma = E \cdot \varepsilon_0 K = 6 \times 10^5 \cdot (8.85 \times 10^{-12}) \cdot 6$, confirming the relationship.

Option B incorrectly assumes a direct multiplication without proper substitution into the original equation, while Option C provides a numerical result without showing the necessary steps to derive it from the equation. Option D is unrelated to the charge density calculation, focusing instead on maximum acceleration in a different context.