AIIMS 2019 Physics Capacitors MCQ Question

The energy stored in a capacitor can be calculated using the formula $E = \frac{1}{2} C V^2$, where $E$ is the energy in joules, $C$ is the capacitance in farads, and $V$ is the voltage in volts. For a 5.0 μF capacitor charged to 800 V, the energy is $E = \frac{1}{2} \times 5.0 \times 10^{-6} \, \text{F} \times (800 \, \text{V})^2 = 1.6 \, \text{J}$, confirming option C as correct. Options A and B are incorrect because they either underestimate or overestimate the energy based on the given values, while option D is significantly higher than the calculated energy.