AIIMS 2018 Physics RMS Voltage MCQ Question

The equation $V = \frac{4V_0}{T} t$ indicates that the voltage $V$ is directly proportional to time $t$ and the maximum voltage $V_0$. At $t = \frac{T}{4}$, substituting this value into the equation gives $V = \frac{4V_0}{T} \cdot \frac{T}{4} = V_0$, confirming that the voltage reaches its maximum value $V_0$ at this point.

Options (A) $\frac{V_0}{\sqrt{3}}$, (B) $\frac{V_0}{2}$, and (C) $\frac{V_0}{\sqrt{2}}$ suggest values less than $V_0$, which do not correspond to the maximum voltage reached in the given equation at $t = \frac{T}{4}$.