AIIMS 2018 Physics Photon Energy MCQ Question

In the given scenario, the energy of the incoming radiation is calculated as $h(1.25 u_0) = 10 \, \text{eV}$, where $W_{ex} = 6 \, \text{eV}$ represents the work function. The maximum kinetic energy ($KE_{max}$) is determined by the equation $KE_{max} = h u - W_{ex}$, resulting in $KE_{max} = 10 \, \text{eV} - 6 \, \text{eV} = 4 \, \text{eV}$. Other options are not applicable as they do not provide relevant values or explanations related to the photon energy and its relationship with work function and kinetic energy.