AIIMS2018Physics-Current Electricity

AIIMS 2018 Physics Internal Resistance MCQ Question

Type: MCQ-numerical-Medium-Class 12

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. The current in the circuit is 0.5 Å. The terminal voltage of the battery when the circuit is closed is

A

10 V

B

zero

C

1.5 V

D

8.5 V

Correct Answer

Option D

Detailed Explanation

To find the terminal voltage (V_t) of the battery, we use the formula Vt=EIrV_t = E - I \cdot r, where EE is the emf (10 V), II is the current (0.5 A), and rr is the internal resistance (3 Ω). Substituting the values gives Vt=10V(0.5A×3Ω)=10V1.5V=8.5VV_t = 10 V - (0.5 A \times 3 Ω) = 10 V - 1.5 V = 8.5 V, which is not listed among the options, making option D correct.

Option A (10 V) is incorrect because it does not account for the voltage drop due to internal resistance. Option B (zero) is incorrect as the battery still provides a voltage when current flows. Option C (1.5 V) is also incorrect, as it misrepresents the voltage drop across the internal resistance rather than the terminal voltage.

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