AIIMS2018Physics-Electricity

AIIMS 2018 Physics Current and Resistance MCQ Question

Type: MCQ-numerical-Medium-Class 12

A 5 V5\text{ V} battery with internal resistance 2 Ω2\ \Omega and a 2 V2\text{ V} battery with internal resistance 1 Ω1\ \Omega are connected to a 10 Ω10\ \Omega resistor as shown in the figure. The current in the 10 Ω10\ \Omega resistor is:

Question diagram
A

0.27 A0.27\text{ A} from P2P_2 to P1P_1

B

0.03 A0.03\text{ A} from P1P_1 to P2P_2

C

0.03 A0.03\text{ A} from P2P_2 to P1P_1

D

0.27 A0.27\text{ A} from P1P_1 to P2P_2

Correct Answer

Option C

Detailed Explanation

The current flowing from P₂ to P₁ is 0.03 A, as determined by applying Ohm's Law (V = IR) to the given circuit parameters, which indicates that the voltage drop across the resistor leads to this specific current direction and magnitude. Option A (0.27 A P₂ to P₁) is incorrect because it overestimates the current based on the circuit's resistance and voltage. Options B and D are also incorrect as they suggest a current flow in the opposite direction, which contradicts the established flow from P₂ to P₁ based on the circuit analysis. Understanding the relationship between voltage, current, and resistance is crucial for analyzing electrical circuits effectively.

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