AIIMS 2018 Physics LR Circuits MCQ Question

In a series LR circuit, the current $I(t)$ can be calculated using the formula $I(t) = \frac{V}{R} \left(1 - e^{-\frac{R}{L}t}\right)$, where $V$ is the voltage, $R$ is the resistance, $L$ is the inductance, and $t$ is time. Substituting the given values $V = 1 \, \text{V}$, $R = 1.5 \, \Omega$, $L = 3 \, \text{H}$, and $t = 2 \, \text{s}$, we find $I(2) = \frac{1}{1.5} \left(1 - e^{-\frac{1.5}{3} \cdot 2}\right) \approx 0.3 \, \text{A}$. Options A (0.4 A) and B (0.5 A) overestimate the current due to incorrect calculations, while option D (N/A) is irrelevant as a valid answer exists.