AIIMS2019Physics-Communication Systems

AIIMS 2019 Physics Amplitude Modulation MCQ Question

Type: MCQ-conceptual-Medium-Class 12

If modulation index μ=12\mu = \frac{1}{2} and VM=2V_M = 2 then VC=?V_C = ?

A

4

B

2

C

6

Correct Answer

Option A

Detailed Explanation

To find the carrier voltage VCV_C in amplitude modulation, we use the formula for the modulation index μ\mu, defined as μ=VmVC\mu = \frac{V_m}{V_C}, where VmV_m is the peak voltage of the modulating signal. Given μ=12\mu = \frac{1}{2} and Vm=2V_m = 2, we can rearrange the formula to find VC=Vmμ=212=4V_C = \frac{V_m}{\mu} = \frac{2}{\frac{1}{2}} = 4.

Options B (2) and C (6) are incorrect because they do not satisfy the relationship defined by the modulation index and the given values of VmV_m and μ\mu. Option D (N/A) is also incorrect as a valid answer exists.

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