AIIMS2019Physics-Work, Energy and Power

AIIMS 2019 Physics Work-Energy Theorem MCQ Question

Type: MCQ-conceptual-Medium-Class 11

Initially spring in its natural length now a block at mass 0.25 kg is released than find out maximum force by system on floor?

Question diagram
A

15 N

B

20 N

C

25 N

D

30 N

Correct Answer

Option C

Detailed Explanation

Option C correctly calculates the spring constant kk using the relationship k=2mgk = 2mg, where m=0.25kgm = 0.25 \, \text{kg} and g=10m/s2g = 10 \, \text{m/s}^2. This gives k=2×0.25×10=5N/mk = 2 \times 0.25 \times 10 = 5 \, \text{N/m}, which aligns with Hooke's Law for springs.

Option A is incorrect because it does not apply the work-energy theorem correctly, as it lacks the context of forces acting on the block. Option B misrepresents the work done by gravity and the potential energy stored in the spring, failing to equate them properly. Option D incorrectly sums the normal force NN without considering the correct equilibrium conditions and the net forces acting on the block.

Found an issue with this question?