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AIIMS2018Physics-Work, Energy and Power

AIIMS 2018 Physics Energy Relations MCQ Question

Type: MCQ-conceptual-Medium-Class 11

When a body is projected vertically up from the ground with certain velocity, its potential energy and kinetic energy at a point Aare in the ratio 2:3. If the same body is projected with double the previous velocity, then at the same point A the ratio of its potential energy to kinetic energy is

A

9:1

B

2:9

C

1:9

D

9:2

Correct Answer

Option C

Detailed Explanation

When the velocity is doubled, the kinetic energy (KE) increases by a factor of four, leading to a new total energy E′=4EE' = 4E. Using the relationship PE/KE=mgh(4E−mgh)PE / KE = \frac{mgh}{(4E - mgh)} and substituting E=5mgh2E = \frac{5mgh}{2} from the initial condition, we find PE/KE=mgh(10mgh−mgh)=mgh9mgh=19PE / KE = \frac{mgh}{(10mgh - mgh)} = \frac{mgh}{9mgh} = \frac{1}{9}.

Options (A) and (B) are incorrect as they do not reflect the correct ratio derived from the energy transformations, while option (D) misrepresents the relationship between potential and kinetic energies after the velocity change. Understanding these energy transformations is crucial in mechanics, particularly in analyzing systems where kinetic and potential energies are interdependent.

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