AIIMS2017Physics-Wave Optics

AIIMS 2017 Physics Young's Double Slit Experiment MCQ Question

Type: MCQ-conceptual-Medium-Class 12

The Young’s double slit experiment is performed with blue and green lights of wavelength 4360 Å and 5460 Å respectively. If x is the distance of 4th4^{th} maxima from the central one, then

A

xblue=xgreenx_{\text{blue}} = x_{\text{green}}

B

xblue>xgreenx_{\text{blue}} > x_{\text{green}}

C

xblue<xgreenx_{\text{blue}} < x_{\text{green}}

D

xblue/xgreenx_{\text{blue}} / x_{\text{green}}

Correct Answer

Option C

Detailed Explanation

In Young's double slit experiment, the position of the maxima is given by the formula x=nλDdx = \frac{n \lambda D}{d}, where nn is the order of the maxima, λ\lambda is the wavelength of light, DD is the distance from the slits to the screen, and dd is the distance between the slits. Since the wavelength of blue light (4360 Å) is shorter than that of green light (5460 Å), the position of the 4th maxima for blue light will be closer to the central maximum compared to that for green light, leading to x(blue)<x(green)x_{(blue)} < x_{(green)}.

Option A is incorrect because the distances are not equal; option B is incorrect as blue light does not produce a greater distance; option D is incomplete and does not provide a direct comparison.

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