AIIMS2018Physics-Wave Optics

AIIMS 2018 Physics Interference MCQ Question

Type: MCQ-conceptual-Medium-Class 12

In Young's double slits experiment, two coherent sources are placed 0.90 mm apart and fringes are observed one metre away. If it produces second dark fringe at a distance of 1 mm from central fringe, the wavelength of monochromatic light used would be

A

60×104 cm60 \times 10^{-4}\text{ cm}

B

10×104 cm10 \times 10^{-4}\text{ cm}

C

10×105 cm10 \times 10^{-5}\text{ cm}

D

6×105 cm6 \times 10^{-5}\text{ cm}

Correct Answer

Option A

Detailed Explanation

For dark fringes in a double-slit interference pattern, the position xx of the dark fringes is given by the formula x=(2n1)λD2dx = \frac{(2n−1) \lambda D}{2d}, where nn is the order of the fringe, λ\lambda is the wavelength of light, DD is the distance from the slits to the screen, and dd is the distance between the slits. This formula arises from the condition for destructive interference, where the path difference must equal an odd multiple of half wavelengths.

Option B incorrectly rearranges the formula, while options C and D provide numerical calculations that do not directly relate to the derivation of the dark fringe position. Understanding the underlying principles of interference is crucial for correctly applying these formulas.

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