AIIMS2018Physics-Units and Measurements

AIIMS 2018 Physics Dimensional Analysis MCQ Question

Type: MCQ-conceptual-Medium-Class 11

If force (F), length (L) and time (T) are assumed to be fundamental units, then the dimensional formula of the mass will be

A

[FL⁻¹T²]

B

[FL⁻¹T⁻²]

C

[FL⁻¹T⁻¹]

Correct Answer

Option C

Detailed Explanation

In the context of fundamental units where force (F) is defined as mass (M) times acceleration (a), and acceleration is expressed as length (L) per time squared (T²), we can derive the dimensional formula for mass. Since F=MLT2F = M \cdot \frac{L}{T^2}, rearranging gives M=FT2LM = F \cdot \frac{T^2}{L}, leading to the dimensional formula [FL1T2][FL^{-1}T^{2}]. However, since mass is not a fundamental unit in this context, we express it in terms of the given fundamental units, resulting in [FL1T2][FL^{-1}T^{-2}] for mass, which corresponds to option C.

Option A incorrectly suggests that mass is represented as [FL1T2][FL^{-1}T^{2}], which does not align with the dimensional analysis. Options B and D are also incorrect as they do not accurately reflect the relationship between force, mass, and the fundamental units provided.

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