AIIMS 2018 Physics Error Analysis MCQ Question

To calculate the percentage error in the measurement, we apply the formula $\frac{\Delta Q}{Q} \times 100 = \frac{2\Delta I}{I} \times 100 + \frac{\Delta R}{R} \times 100 + \frac{\Delta t}{t} \times 100$. Assuming the individual percentage errors for current ($I$), resistance ($R$), and time ($t$) are each 2%, we find that the total percentage error sums to $2\% + 2\% + 2\% = 6\%$. However, since the formula includes a factor of 2 for the current measurement, the total percentage error becomes $2 \times 2\% + 2\% + 2\% = 8\%$, confirming option D as correct. Other options are incorrect as they do not account for the additional factor from the current measurement, leading to underestimations of the total error.