AIIMS2004Physics-Thermodynamics

AIIMS 2004 Physics Stefan-Boltzmann Law MCQ Question

Type: MCQ-numerical-Medium-Class 11

Suppose the sun expands so that its radius becomes 100 times its present radius and its surface temperature becomes half of its present value. The total energy emitted by it then will increase by a factor of

A

10⁴

B

625

C

256

D

16

Correct Answer

Option B

Detailed Explanation

To solve the question, we need to apply the Stefan-Boltzmann Law, which states that the total power radiated per unit area of a black body is proportional to the fourth power of its absolute temperature. The formula can be expressed as:

P=σAT4P = \sigma A T^4

where:

  • PP is the total power (energy emitted per second),
  • σ\sigma is the Stefan-Boltzmann constant,
  • AA is the surface area of the radiating body, and
  • TT is the absolute temperature.

Step 1: Calculate Initial Conditions

  1. Initial Radius: Let the initial radius of the sun be RR.
  2. Initial Temperature: Let the initial temperature of the sun be TT.

Using the formula for surface area AA of a sphere:

A=4πR2A = 4 \pi R^2

The initial power emitted by the sun can be expressed as:

Pinitial=σ(4πR2)T4P_{\text{initial}} = \sigma (4 \pi R^2) T^4

Step 2: Calculate New Conditions

Now, according to the problem:

  • The new radius becomes R=100RR' = 100R.
  • The new temperature becomes T=12TT' = \frac{1}{2} T.

The new surface area will be:

A=4π(R)2=4π(100R)2=4π(10000R2)=10000(4πR2)A' = 4 \pi (R')^2 = 4 \pi (100R)^2 = 4 \pi (10000 R^2) = 10000 (4 \pi R^2)

The new power emitted will be:

Pnew=σ(A)(T)4=σ(10000(4πR2))(12T)4P_{\text{new}} = \sigma (A') (T')^4 = \sigma (10000 (4 \pi R^2)) \left( \frac{1}{2} T \right)^4

Calculating (12T)4\left( \frac{1}{2} T \right)^4:

(12T)4=116T4\left( \frac{1}{2} T \right)^4 = \frac{1}{16} T^4

Substituting this into the equation for PnewP_{\text{new}}:

Pnew=σ(10000(4πR2))(116T4)P_{\text{new}} = \sigma (10000 (4 \pi R^2)) \left( \frac{1}{16} T^4 \right)

Now simplifying:

Pnew=σ(4πR2)T410000116=Pinitial10000116P_{\text{new}} = \sigma (4 \pi R^2) T^4 \cdot 10000 \cdot \frac{1}{16} = P_{\text{initial}} \cdot 10000 \cdot \frac{1}{16}

Step 3: Calculate the Increase Factor

Now, calculating the factor by which the total energy emitted increases:

Factor=PnewPinitial=10000116=625\text{Factor} = \frac{P_{\text{new}}}{P_{\text{initial}}} = 10000 \cdot \frac{1}{16} = 625

Conclusion

Thus, the total energy emitted by the sun when it expands to 100 times its radius and its temperature decreases to half is increased by a factor of 625.

Correct Answer: B) 625

Clarification of Incorrect Options

  • A) 10⁴: This would imply that the energy emitted increases by a factor of 10410^4 without accounting for the temperature reduction. This option does not consider the 116\frac{1}{16} factor from the temperature change.

  • C) 256: This factor might arise from a misunderstanding of (12)4=116\left( \frac{1}{2} \right)^4 = \frac{1}{16}, but does not correctly apply the area increase.

  • D) 16: This option considers only the decrease in temperature without factoring in the increase in area.

In summary, the correct answer is derived from applying the Stefan-Boltzmann Law accurately, considering both changes in radius and temperature.

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