AIIMS2019Physics-Thermodynamics

AIIMS 2019 Physics Specific Heat Ratio MCQ Question

Type: MCQ-numerical-Medium-Class 11

Find γ\gamma for the mixture of 11 gmCO211\text{ gmCO}_2 and 14 gmN214\text{ gmN}_2?

A

γmix=75\gamma_{\text{mix}} = \frac{7}{5}

B

γmix=107\gamma_{\text{mix}} = \frac{10}{7}

C

γmix=118\gamma_{\text{mix}} = \frac{11}{8}

D

γmix=43\gamma_{\text{mix}} = \frac{4}{3}

Correct Answer

Option C

Detailed Explanation

To find the specific heat ratio (γ_mix) for the mixture of gases, we apply the formula n1+n2γmix1=n1γ11+n2γ21\frac{n_1 + n_2}{\gamma_{\text{mix}} - 1} = \frac{n_1}{\gamma_1 - 1} + \frac{n_2}{\gamma_2 - 1}. Here, n1=0.25n_1 = 0.25 moles of CO₂ (with γ1=1.3\gamma_1 = 1.3) and n2=0.50n_2 = 0.50 moles of N₂ (with γ2=1.4\gamma_2 = 1.4). Substituting these values into the equation and solving yields γmix=1.6\gamma_{\text{mix}} = 1.6.

Options A (1.4), B (1.5), and D (1.7) are incorrect as they do not satisfy the derived relationship based on the specific heat ratios of the individual gases and their mole fractions in the mixture.

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