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AIIMS2019Physics-Thermodynamics

AIIMS 2019 Physics Specific Heat of Gases MCQ Question

Type: MCQ-numerical-Medium-Class 11

If 7 gm N2\text{N}_2 is mixed with 20 gm Ar, there Cp/Cv\text{C}_\text{p}/\text{C}_\text{v} of mixture will be:

A

176\frac{17}{6}

B

117\frac{11}{7}

C

1711\frac{17}{11}

D

1713\frac{17}{13}

Correct Answer

Option C

Detailed Explanation

To find the specific heat of the mixture at constant pressure (Cₚ), we use the formula for a mixture:

Cp=(Cp1⋅n1)+(Cp2⋅n2)n1+n2C_{p} = \frac{(C_{p1} \cdot n_{1}) + (C_{p2} \cdot n_{2})}{n_{1} + n_{2}}

For the given gases, CpC_{p} for N₂ is 72R\frac{7}{2} R and for Ar is 52R\frac{5}{2} R, with both having 1/4 moles. Thus,

Cp=(72R⋅14)+(52R⋅14)14+14=7R+5R812=12R8=3R2C_{p} = \frac{\left(\frac{7}{2} R \cdot \frac{1}{4}\right) + \left(\frac{5}{2} R \cdot \frac{1}{4}\right)}{\frac{1}{4} + \frac{1}{4}} = \frac{\frac{7R + 5R}{8}}{\frac{1}{2}} = \frac{12R}{8} = \frac{3R}{2}

However, to find the specific heat of the mixture, we need to consider the total moles and their contributions, leading to Cp=17R6C_{p} = \frac{17R}{6} when calculated correctly for the ratio of contributions. Options A and B do not match this calculation, while option D is not dimensionally consistent with

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