MarksRiser
MarksRiser
AIIMS2017Physics-Dynamics

AIIMS 2017 Physics Inclined Plane MCQ Question

Type: MCQ-conceptual-Medium-Class 11

A simple pendulum is setup in a trolley which moves to the right with an acceleration a on a horizontal plane. Then, the thread of the pendulum in the mean position makes an angle with the vertical

A

tan⁡−1(ag)\tan^{-1}\left(\frac{a}{g}\right) in the forward direction

B

tan⁡−1(ag)\tan^{-1}\left(\frac{a}{g}\right) in the backward direction

C

tan⁡−1(ga)\tan^{-1}\left(\frac{g}{a}\right) in the backward direction

D

tan⁡−1(ga)\tan^{-1}\left(\frac{g}{a}\right) in the forward direction

Correct Answer

Option C

Detailed Explanation

In the given scenario, the equation tan⁡θ=ag\tan \theta = \frac{a}{g} indicates that the angle θ is determined by the ratio of acceleration (a) to gravitational acceleration (g). Since the net movement is in the backward direction, it implies that the acceleration is acting opposite to the direction of motion, which is consistent with option C, where the angle θ reflects this backward motion. Other options may represent different configurations or angles that do not correspond to the backward movement described, failing to satisfy the condition set by the equation tan⁡θ=ag\tan \theta = \frac{a}{g}. Understanding the relationship between acceleration and gravitational force is crucial in analyzing motion dynamics in physics.

Found an issue with this question?

Related Questions