AIIMS2018Physics-Thermodynamics

AIIMS 2018 Physics First Law of Thermodynamics MCQ Question

Type: MCQ-numerical-Medium-Class 11

If 1 cm31\text{ cm}^3 of water is vaporized (latent heat of vaporization = 540 cal/g540\text{ cal/g}) at P=1 atmP = 1\text{ atm}. If the volume of steam formed is 1671 cm31671\text{ cm}^3, calculate the increase in internal energy.

A

273 cal

B

373 cal

C

473 cal

D

573 cal

Correct Answer

Option B

Detailed Explanation

In the given problem, ΔQ represents the heat absorbed by the system, calculated as ΔQ = m × Lᵥ, where m is the mass and Lᵥ is the latent heat of vaporization. The equation ΔQ = Δu + Δw relates the change in internal energy (Δu) to the heat added and the work done, leading to the calculation of Δu as 373 cal after substituting the values. Other options are not applicable as they do not provide relevant information or calculations related to the problem at hand, making option B the only viable choice based on the derived internal energy change.

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