AIIMS2009Physics-Thermodynamics
AIIMS 2009 Physics Entropy MCQ Question
Type: MCQ-numerical-Medium-Class 11
In an isobaric process, when temperature changes from T₁ to T₂, ΔS is equal to
A
2.303 Cp log (T₂/T₁)
B
2.303 Cp ln (T₂/T₁)
C
Cp ln (T₂/T₁)
D
Cv ln (T₂/T₁)
Correct Answer
Option A
Detailed Explanation
The entropy change for a process, when T and P are the variables is given by ΔS = Cp ln T2/T1 - R ln P2/P1.
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