AIIMS 2019 Physics Centripetal Force MCQ Question

To determine the maximum distance from the axis where the block can be placed without sliding, we use the centripetal force required for circular motion, which is provided by the frictional force. The maximum static frictional force $F_f$ is given by $F_f = \mu_k \cdot m \cdot g$, where $\mu_k = 0.4$, $m = 2 \, \text{kg}$, and $g \approx 9.81 \, \text{m/s}^2$. The centripetal force needed for the block at a distance $r$ from the axis is $F_c = m \cdot \omega^2 \cdot r$, where $\omega = 10 \, \text{rad/s}$. Setting $F_f = F_c$ and solving for $r$ yields a maximum distance of 0.04 m (or 4 cm), confirming option C as correct.

Options A (2 cm), B (3 cm), and D (6 cm) are incorrect as they do not satisfy the derived relationship between the frictional force and the centripetal force for the given parameters.