AIIMS 2018 Physics Angular Acceleration MCQ Question

To find the number of revolutions made by the wheel in 10 seconds, we first calculate the linear distance traveled by the elevator using the equation of motion: $s = ut + \frac{1}{2} a t^2$. With an initial velocity $u = 0$, acceleration $a = 2 \, \text{m/s}^2$, and time $t = 10 \, \text{s}$, the distance $s$ is $s = 0 + \frac{1}{2} \times 2 \times (10)^2 = 100 \, \text{m}$. The circumference of the wheel is $C = 2 \pi r = 2 \pi (0.1) \approx 0.628 \, \text{m}$. The number of revolutions is then $\frac{s}{C} = \frac{100}{0.628} \approx 159$, confirming option C as correct. Other options are incorrect as they do not match the calculated number of revolutions based on the given parameters.