AIIMS2001Physics-Planck's Oscillator

AIIMS 2001 Physics Energy Quantization MCQ Question

Type: MCQ-numerical-Hard-Class 12

In Planck's oscillator energy is given as E = huexp(hukT)1\frac{h u}{\exp(\frac{h u}{kT}) - 1}. If K = 0, then energy would be

A

B

0

C

K/ν

D

Correct Answer

Option B

Detailed Explanation

In Planck's oscillator model, the energy is given by the formula E=huexp(hukT)1E = \frac{h u}{\exp(\frac{h u}{kT}) - 1}. When K=0K = 0, this implies that the temperature TT approaches absolute zero. As TT approaches 0, the term exp(hukT)\exp(\frac{h u}{kT}) becomes very large, leading to the denominator approaching infinity. Thus, the energy EE approaches 0. Therefore, the correct answer is B) 0.

The other options can be analyzed as follows:

  • A) huh u: This is incorrect because at absolute zero, the energy does not equal huh u.
  • C) K/uK/ u: This is not applicable since KK is 0, making this expression also equal to 0, but it's not the correct interpretation of the energy formula.
  • D) \infty: This is incorrect as the energy does not approach infinity; instead, it approaches 0 as explained above.

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