AIIMS 2019 Physics Threshold Wavelength MCQ Question
When a metallic surface is illuminated by a light of wavelength λ, the stopping potential for the photoelectric current is 3 V. When the same surface is illuminated by light of wavelength 2λ, the stopping potential is 1 V. The threshold wavelength for this surface is
4λ
3.5λ
3λ
2.75λ
Correct Answer
Detailed Explanation
When light of wavelength λ is incident on the metallic surface, the stopping potential (V₁) is 3 V, indicating that the energy of the incident photons (E₁ = hν₁ = hc/λ) exceeds the work function (ϕ) by 3 eV. For the light of wavelength 2λ, the stopping potential (V₂) is 1 V, meaning E₂ = hν₂ = hc/(2λ) exceeds ϕ by 1 eV. By applying the photoelectric equation, we find that the threshold wavelength (λ₀) can be derived from the relationship between the stopping potentials and wavelengths, leading to λ₀ = 4λ. Other options are incorrect as they do not satisfy the energy balance derived from the stopping potentials and the corresponding photon energies.
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