AIIMS2018Physics-Oscillations

AIIMS 2018 Physics Simple Harmonic Motion MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The velocity vector v and displacement vector x of a particle executing SHM are related as $\frac{dv}{dx} = -\omega^2 x$ with the initial condition $V = v₀$ at $x = 0$ . The velocity v, when displacement is x, is

$v = \sqrt{v₀^²⁺ \omega^2 x^2}$

$v = \omega x$

$v = \sqrt{v₀^²⁻ \omega^2 x^2}$

$v = v₀$

Correct Answer

Option

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