A simple pendulum has a bob suspended by an inextensible thread of length metre from a point A of suspension. At the extreme position of oscillation, the thread is suddenly caught by a peg at a point

Question

A simple pendulum has a bob suspended by an inextensible thread of length metre from a point A of suspension. At the extreme position of oscillation, the thread is suddenly caught by a peg at a point B distant (1/4) m from A and the bob begins to oscillate in the new condition. The change in frequency of oscillation of the pendulum is approximately given by (g = 10 m/s²).

A

$\frac{\sqrt{10}}{2} \text{ hertz}$

B

$\frac{1}{4\sqrt{10}} \text{ hertz}$

C

$\frac{\sqrt{10}}{3} \text{ hertz}$

D

$\frac{1}{\sqrt{10}} \text{ hertz}$

Accepted Answer

$\frac{1}{4\sqrt{10}} 	ext{ hertz}$

Answer

$\frac{\sqrt{10}}{2} 	ext{ hertz}$

Answer

$\frac{\sqrt{10}}{3} 	ext{ hertz}$

Answer

$\frac{1}{\sqrt{10}} 	ext{ hertz}$

AIIMS 2000 Physics Simple Harmonic Motion MCQ Question

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