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AIIMS2018Physics-Oscillations

AIIMS 2018 Physics Potential Energy in Oscillations MCQ Question

Type: MCQ-conceptual-Medium-Class 11

A particle of mass is executing oscillations about the origin on the x-axis. Its potential energy is V(x)=k|x|^3, where k is a positive constant. If the amplitude of oscillation is a, then its time period T is

A

proportional to 1/√a

B

proportional to √a

C

independent a^(3/2)

D

None of these

Correct Answer

Option A

Detailed Explanation

For a particle oscillating in a potential V(x)=k∣x∣3V(x) = k|x|^3, the force can be derived from the potential as F=−dVdx=−3k∣x∣2sgn(x)F = -\frac{dV}{dx} = -3k|x|^2 \text{sgn}(x). This force leads to non-linear oscillations, and using the method of dimensional analysis, we find that the time period TT is proportional to a−1/2a^{-1/2}, where aa is the amplitude. Thus, T∝1aT \propto \frac{1}{\sqrt{a}}, confirming option (A).

Option (B) is incorrect because it suggests a direct proportionality to a\sqrt{a}, which does not align with the derived relationship. Option (C) is incorrect as it implies independence from aa, which contradicts the dependence established through dimensional analysis.

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