AIIMS2018Physics-Optics

AIIMS 2018 Physics Polarization MCQ Question

Type: MCQ-conceptual-Medium-Class 12

Light is incident on a polarizer. A second prism called analyzer is kept at an angle of 1515^\circ from the first polarizer then the intensity of final emergent light will be:

A

0.46I00.46I_0

B

0.36I00.36I_0

C

0.56I00.56I_0

D

0.96I00.96I_0

Correct Answer

Option A

Detailed Explanation

In the given optical setup, the intensity of the emergent light can be determined using Malus's Law, which states that the transmitted intensity II through a polarizer is given by I=I0cos2θI = I_0 \cos^2 \theta, where θ\theta is the angle between the light's polarization direction and the axis of the polarizer. For two polarizers, if the first polarizer transmits intensity I0I_0 and the second is oriented at 1515^\circ relative to the first, the final intensity becomes I=I02cos215I = \frac{I_0}{2} \cos^2 15^\circ, confirming option A as correct.

Options B and C incorrectly apply the cosine factor or miscalculate the intensity after two polarizers, while option D introduces an unnecessary factor that does not align with the principles of intensity transmission through polarizers.

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