AIIMS 2018 Physics Lens and Mirror Formula MCQ Question

The calculation of the effective focal length $f$ using the formula $\frac{1}{f} = \frac{2}{f_e} + \frac{1}{f_m}$ leads to $f = -6 \, \text{cm}$. Applying the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ with $u = -20 \, \text{cm}$ results in $v = -8.6 \, \text{cm}$, indicating that the image is virtual and located on the same side as the object. Other options are not applicable as they do not provide valid solutions or relevant information related to the problem.