AIIMS 2019 Physics Camera Optics MCQ Question

For a camera with an F number of F/4, the relationship $F = \frac{f}{D_1}$ gives $D_1 = \frac{f}{4}$. For the F/5.6 camera, $D_2 = \frac{f}{5.6}$. The ratio $\frac{D_2}{D_1} = \frac{4}{5.6}$ simplifies to $D_2 = D_1 \times \frac{4}{5.6}$, which can be further reduced to $D_2 = D_1 \times \frac{1}{1.412}$ or $D_2 = \frac{D_1}{\sqrt{2}}$, confirming that option D is correct. Other options are not applicable as they do not provide relevant information or calculations related to the F number and aperture diameter relationship.