AIIMS 2017 Physics Tension in Ropes MCQ Question

To find the tension in the rope at t = 8 s, we apply Newton's second law. The lift is accelerating upward, so the tension (T) must overcome both the gravitational force (weight) acting on the lift and the force due to acceleration. The weight is calculated as $W = mg = 1600 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 15696 \, \text{N}$. If the lift is accelerating upward at $a \, \text{m/s}^2$, the tension can be expressed as $T = W + ma = 15696 \, \text{N} + 1600 \, \text{kg} \times a$. Assuming the acceleration at t = 8 s is $1 \, \text{m/s}^2$ (as indicated in the velocity graph), we find $T = 15696 \, \text{N} + 1600 \, \text{N} = 11200 \, \text{N}$. Other options are incorrect as they do not account for the upward acceleration or miscalculate the forces involved.