AIIMS 2019 Physics Equations of Motion MCQ Question

Option C is correct because it aligns with the understanding that when acceleration is constant (non-zero), the displacement-time graph is indeed a parabola, as described by the equation $s = ut + \frac{1}{2} at^2$. In contrast, if the acceleration is zero, the body moves with uniform velocity, resulting in a linear displacement-time graph, which corresponds to option A. Since options B and D are not applicable or relevant, they do not provide any additional information or correct statements regarding the motion described. Understanding these relationships helps clarify the nature of motion under varying acceleration conditions.